0=2n^2(2n-1)

Solution for 0=2n^2(2n-1) equation:

Simplifying
0 = 2n2(2n + -1)

Reorder the terms:
0 = 2n2(-1 + 2n)
0 = (-1 * 2n2 + 2n * 2n2)
0 = (-2n2 + 4n3)

Solving
0 = -2n2 + 4n3

Solving for variable 'n'.
Remove the zero:
2n2 + -4n3 = -2n2 + 4n3 + 2n2 + -4n3

Reorder the terms:
2n2 + -4n3 = -2n2 + 2n2 + 4n3 + -4n3

Combine like terms: -2n2 + 2n2 = 0
2n2 + -4n3 = 0 + 4n3 + -4n3
2n2 + -4n3 = 4n3 + -4n3

Combine like terms: 4n3 + -4n3 = 0
2n2 + -4n3 = 0

Factor out the Greatest Common Factor (GCF), '2n2'.
2n2(1 + -2n) = 0

Ignore the factor 2.
Subproblem 1
Set the factor 'n2' equal to zero and attempt to solve:

Simplifying
n2 = 0

Solving
n2 = 0

Move all terms containing n to the left, all other terms to the right.

Simplifying
n2 = 0

Take the square root of each side:
n = {0}
Subproblem 2
Set the factor '(1 + -2n)' equal to zero and attempt to solve:

Simplifying
1 + -2n = 0

Solving
1 + -2n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2n = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2n = 0 + -1
-2n = 0 + -1

Combine like terms: 0 + -1 = -1
-2n = -1

Divide each side by '-2'.
n = 0.5

Simplifying
n = 0.5
Solution
n = {0, 0.5}